C) exp(XY)/exp(X) d) exp(X 3*Y 2*Z)/exp(X 2*Y 2*Z) e) 2log(3X Y) log(X) log(Z/3) 2 Suppose log(p/(1 p)) = r Show that p = exp(r)/(1 exp(r))Join this channel to get access to perkshttps//wwwyoutubecom/channel/UCFhqELShDKKPv0JRCDQgFoQ/joinHere is the technique to find the area under 3 curves aExtended Keyboard Examples Upload Random Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, music
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(x/2 y/3)^3-(x/2-y/3)^3 simplify-Subtract x^ {3} from both sides Subtract x 3 from both sides Combine x^ {3} and x^ {3} to get 0 Combine x 3 and − x 3 to get 0 Reorder the terms Reorder the terms This is true for any x This is true for any x Use the distributive property to multiply xy by x^ {2}xyy^ {2A(3a2) Now replace a by (xy) and expression becomes (xy)(3(xy)2) = (xy)(3x3y2) If you recognize that (xy) is a factor throughout you can immediately pull it out (xy) and then divide the expression by the factor and put the result in brackets following (xy) getting (xy)(3(xy)2) = (xy)(3x3y2)
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Calculate the sum for each pair The solution is the pair that gives sum 1 The solution is the pair that gives sum 1 Rewrite 2x^ {2}x3 as \left (2x^ {2}2x\right)\left (3x3\right) Rewrite 2 x 2 x − 3 as ( 2 x 2 − 2 x) ( 3 x − 3) Factor out 2x in the first and 3 in the second groupView more examples » Access instant learning tools Get immediate feedback and guidance with stepbystep solutions and Wolfram Problem Generator LearnSimplify\\frac{x^214x49}{49x^2} simplify\\frac{6}{x1}\frac{3}{x1} simplify\\frac{5x}{6}\frac{3x}{2} simplifycalculator en Related Symbolab blog posts Middle School Math Solutions – Equation Calculator Welcome to our new "Getting Started" math solutions series Over the next few weeks, we'll be showing how Symbolab
2xy=3 Geometric figure Straight Line Slope = 2 xintercept = 3/2 = yintercept = 3/1 = Rearrange Rearrange the equation by subtracting what is to the right of theIdentities Proving Identities Trig Equations Trig Inequalities Evaluate Functions Simplify Statistics y=2x^{2}5x3 en Related Symbolab blog posts High School Math Solutions – Quadratic Equations Calculator, Part 1Integrate 1/(cos(x)2) from 0 to 2pi;
The two curves `x^(3)3xy^(2)2=0 and 3x^(2)yy^(3)=2`Welcome to Doubtnut Doubtnut is World's Biggest Platform for Video Solutions of Physics, Chemistry, Ma(Remember to use the chain rule on D ( y 2/3) ) (2/3)x1/3 (2/3)y1/3 y' = 0 , so that (Now solve for y' ) (2/3)y1/3 y' = (2/3)x1/3, , and , Since lines tangent to the graph will have slope $ 1 $ , set y' = 1 , getting , y 1/3 = x 1/3, y 1/3 = x 1/3, ( y 1/3) 3 = ( x 1/3) 3, or y = x Substitue this into the ORIGINAL equation x 2/3This is the question The straight line y=2p1 intersects the curve y= x (p^2/x) at two distinct points Find the range of values of p this is what i did 2p 1 = x p^2/x simplify x^2 (2p1)x p^2 = 0 b^24ac > 0 Please check answers) Perform the indicated operations and simplify
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The answer is 3^5 (which is also = 243) Stepbystep explanation We can use the exponent or product rule for powers (2 and 3) that have the same base (3) in order to multiply similar bases that have their respective powers, add the exponents, which in this case are 2 and 3, viz 3^2 x 3^3 = 3^ (23) = 3^5 3^5 = 3 × 3 × 3 × 3 × 3 = 243Then type x=3 Try it now 2x @ x=3 Clickable Demo Try entering 2x @ x=3 into the text box After you enter the expression, Algebra Calculator will evaluate 2x for x=3 2(3) = 6 More Examples Here are more examples of how to evaluate expressions in Algebra Calculator Feel free to try them now Evaluate 3xy for x=2, y=3 3xy @ x=2, y=3Algebra Calculator is a calculator that gives stepbystep help on algebra problems See More Examples » x3=5 1/3 1/4 y=x^21 Disclaimer This calculator is not perfect Please use at your own risk, and please alert us if something isn't working Thank you
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8x2y2/4x3y3 Final result 2x5y5 Step by step solution Step 1 y2 Simplify —— 4 Equation at the end of step 1 y2 ( ( (8 • (x2)) • ——) • x3) • y3 4 Step 2 Equation at the end of step 2 y2 Finding limit of \frac {x^2y^2} {x^3y^3} as (x,y)\to (0,0) duplicate Finding limit of x3y3x2y2First type the equation 2x3=15 Then type the @ symbol Then type x=6 Try it now 2x3=15 @ x=6 Clickable Demo Try entering 2x3=15 @ x=6 into the text box After you enter the expression, Algebra Calculator will plug x=6 in for the equation 2x3=15 2(6)3 = 15 The calculator prints "True" to let you know that the answer is right More ExamplesX^3 x^2 y x y^2 y^3 Natural Language;
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Algebra Factor x^3y^3 x3 − y3 x 3 y 3 Since both terms are perfect cubes, factor using the difference of cubes formula, a3 −b3 = (a−b)(a2 abb2) a 3 b 3 = ( a b) ( a 2 a b b 2) where a = x a = x and b = y b = y (x−y)(x2 xyy2) ( x y) ( x 2 x y y 2)Simplify the expression with exponentNeed more help?I can't figure this one out on my own either $$\frac{(3x^{3/2}y^3)} {(x^2y^{1/2})}^{2}$$ I am a little confused on all the small rules at play here but I know that a negative exponent will flip a fraction so I square the top and then flip it
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The simplified expressions are i) x 3 5x 2 5x ii) a 2 b 3 3a 2 5b 3 iii) t 3 st s 2 t 2 s 3 iv) 4ac v) 3x 2 y 2 4xy vi) x 3 y 3 vii) 225x 2 16y 2 viii) a 2 b 2 c 2 2ab ☛ Check NCERT Solutions for Class 8 Maths Chapter 9Mr Dwyer is available for 1on1 tutoring online Details at https//www4tutorcom/onlinetutoring Explanation Try to simply the expression 3x−2y3 2xy first, then worry about the −2 exponent Notice that you can write 3x−2y3 2xy = 3 ⋅ y3 2xy ⋅ 1 x2 = 3y2 2x3 The original expression now becomes (3y2 2x3)−2 = ( 2x3 3y2)2 = 22 ⋅ x3⋅2 32 ⋅ y2⋅2 = 4x6 9y4 Answer link
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Find an answer to your question PLS HELP simplify x^2(y^3)^4/xy^5= x^a*y^b a= b= if a1 = 5 and an = 5(12)^n1, then what is the sum of First, we can rewrite the term as x2× 1 3 Next, we can use this rule of exponents to rewrite the term again xa×b = (xa)b x2× 1 3 ⇒ (x2)1 3 Now, we can use this rule to write the term as an radical x1 n = n√x (x2)1 3 = 3√(x2) Answer linkAlgebra Calculator get free stepbystep solutions for your algebra math problems
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Apply the product rule to 3 x 2 3 x 2 Raise 3 3 to the power of 3 3 Multiply the exponents in (x2)3 ( x 2) 3 Tap for more steps Apply the power rule and multiply exponents, ( a m) n = a m n ( a m) n = a m n Multiply 2 2 by 3 3 Multiply the exponents in (y3)3 ( y 3) 3Simplify ⓐ 48 m 7 n 2 100 m 5 n 8 48 m 7 n 2 100 m 5 n 8 ⓑ 54 x 7 y 5 250 x 2 y 2 3 54 x 7 y 5 250 x 2 y 2 3 ⓒ 32 a 9 b 7 162 a 3 b 3 4 32 a 9 b 7 162 a 3 b 3 4 In the next example, there is nothing to simplify in the denominatorsAlgebra Graph y=3/2x2 y = − 3 2 x − 2 y = 3 2 x 2 Rewrite in slopeintercept form Tap for more steps The slopeintercept form is y = m x b y = m x b, where m m is the slope and b b is the yintercept y = m x b y = m x b Write in y = m x b y = m x b form Tap for more steps
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Simplify (4 x 2 y 5) 3 (4 x 2 y 5) 3 If you missed this problem, review Example 518 Be Prepared Simplify 5 −3 5 −3 If you missed this problem, review Example 514 Simplify Expressions with a 1 n a 1 n Rational exponents are another way of writing expressions with radicals When we use rational exponents, we can apply theSOLUTION 1 Begin with x 3 y 3 = 4 Differentiate both sides of the equation, getting D ( x 3 y 3) = D ( 4 ) , D ( x 3) D ( y 3) = D ( 4 ) , (Remember to use the chain rule on D ( y 3) ) 3x 2 3y 2 y' = 0 , so that (Now solve for y' ) 3y 2 y' = 3x 2, and Click HERE to return to the list of problems SOLUTION 2 Begin with (xy) 2 = x y 1 Differentiate both sides #(x^2y^22xy)(xy)=x^3x^2yxy^2y^32x^2y2xy^2# #rArr x^3y^33x^2y3xy^2# Always expand each term in the bracket by all the other terms in the other brackets, but never multiply two or more terms in the same bracket
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(x y) 3 = x 3 3x 2 y 3xy 2 y 3 Example (1 a 2 ) 3 = 1 3 31 2 a 2 31(a 2 ) 2 (a 2 ) 3 = 1 3a 2 3a 4 a 6 (x y z) 2 = x 2 y 2 z 2 2xy 2xz 2yzYour equation to simplify (x3)^3 Cubing an expression is the same as multiplying the expression by itself 3 times (x3)(x3)(x3) Multiply each term in the first group by each term in the second group using the FOIL method FOIL stands for First OuterExample A circle with center at (3,4) and a radius of 6 Start with (x−a) 2 (y−b) 2 = r 2 Put in (a,b) and r (x−3) 2 (y−4) 2 = 6 2 We can then use our algebra skills to simplify and rearrange that equation, depending on what we need it for
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To generate Pascal's Triangle, we start by writing a 1 In the row below, row 2, we write two 1's In the 3 rd row, flank the ends of the rows with 1's, and add latex11/latex to find the middle number, 2 In the latexn\text{th}/latex row, flank the ends of the row with 1'sCovariance and Correlation Math 217 Probability and Statistics Prof D Joyce, Fall 14 Covariance Let Xand Y be joint random variables Their covariance Cov(X;Y) is de ned bySimplify (xy)^2 Rewrite as Expand using the FOIL Method Tap for more steps Apply the distributive property Apply the distributive property Apply the distributive property Simplify and combine like terms Tap for more steps Simplify each term Tap for more steps Multiply by
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Identities Proving Identities Trig Equations Trig Inequalities Evaluate Functions Simplify x2y=2x5, xy=3 en Related Symbolab blog posts High School Math Solutions – Systems of Equations Calculator, Elimination A system of equations is a collection of two or more equations with the same set of variables In this blog post,Typo/misspeak around 4 minutes 369=27Multivariable Calculus Find all local maxima/minima and saddle points for the function f(x,y) = x^3 3xy y^3 W Dafrisdavid X When trying to solve this problem, you should think of the laws of indices It will assist in solving this problem Below is a picture of the laws So, let solve the problem so since x is the common term in the numerator we can use the third rule in the left column = ⎛ ⎜ ⎜ ⎜ ⎜⎝ 3(x( 1 3 (− 2 3))) 3x
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Integrate x^2 sin y dx dy, x=0 to 1, y=0 to pi;2/x3/y=15;8/x5/y=77 solve by using cramer's methodAll equations of the form a x 2 b x c = 0 can be solved using the quadratic formula 2 a − b ± b 2 − 4 a c The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction x^ {2}2xy^ {2}2y3=0 x 2 − 2 x y 2 2 y − 3 = 0 This equation is in standard form ax^ {2}bxc=0
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Graph y=x^23 y = x2 − 3 y = x 2 3 Find the properties of the given parabola Tap for more steps Rewrite the equation in vertex form Tap for more steps Complete the square for x 2 − 3 x 2 3 Tap for more steps Use the form a x 2 b x c a x 2 b xX^2 2 y^2 = 1 Natural Language; Simplify (x− 1 2y4)1 4 x2 3y3 2x−3 2y1 2 First, let's distribute the 1 4 exponent x( − 1 2)1 4 y(4)1 4 x2 3y3 2x− 3 2y1 2 When you raise a power to a power you multiply them to find the exponent Let's do that x( − 1 2)( 1 4)y(4) (1 4) x2 3y3 2x− 3 2y1 2 x− 1 8y1 x2 3y3 2x− 3 2y1 2 x− 1 8y x2 3y3 2x− 3 2y1 2
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